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113015142535 = 522603028507
BaseRepresentation
bin110100101000000111…
…0100011100010000111
3101210201012221002100211
41221100032203202013
53322423334030120
6123530214420251
711110422601321
oct1512016434207
9353635832324
10113015142535
1143a25113349
1219aa0661687
13a871083909
14568180c611
152e16b7d25a
hex1a503a3887

113015142535 has 4 divisors (see below), whose sum is σ = 135618171048. Its totient is φ = 90412114024.

The previous prime is 113015142517. The next prime is 113015142551. The reversal of 113015142535 is 535241510311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113015142535 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113015142497 and 113015142506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11301514249 + ... + 11301514258.

It is an arithmetic number, because the mean of its divisors is an integer number (33904542762).

Almost surely, 2113015142535 is an apocalyptic number.

113015142535 is a deficient number, since it is larger than the sum of its proper divisors (22603028513).

113015142535 is an equidigital number, since it uses as much as digits as its factorization.

113015142535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22603028512.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 113015142535 its reverse (535241510311), we get a palindrome (648256652846).

The spelling of 113015142535 in words is "one hundred thirteen billion, fifteen million, one hundred forty-two thousand, five hundred thirty-five".

Divisors: 1 5 22603028507 113015142535