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1130202202331 is a prime number
BaseRepresentation
bin10000011100100101010…
…011010000000011011011
311000001020201211121120002
4100130211103100003123
5122004123230433311
62223112511323215
7144440315132366
oct20344523200333
94001221747502
101130202202331
113a6352751694
1216305a52050b
1382768018c07
143c9b87090dd
151e5ec21b93b
hex107254d00db

1130202202331 has 2 divisors, whose sum is σ = 1130202202332. Its totient is φ = 1130202202330.

The previous prime is 1130202202319. The next prime is 1130202202333. The reversal of 1130202202331 is 1332022020311.

It is a strong prime.

It is an emirp because it is prime and its reverse (1332022020311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1130202202331 - 218 = 1130201940187 is a prime.

It is a super-2 number, since 2×11302022023312 (a number of 25 digits) contains 22 as substring.

Together with 1130202202333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1130202202333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565101101165 + 565101101166.

It is an arithmetic number, because the mean of its divisors is an integer number (565101101166).

Almost surely, 21130202202331 is an apocalyptic number.

1130202202331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130202202331 is an equidigital number, since it uses as much as digits as its factorization.

1130202202331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1130202202331 its reverse (1332022020311), we get a palindrome (2462224222642).

The spelling of 1130202202331 in words is "one trillion, one hundred thirty billion, two hundred two million, two hundred two thousand, three hundred thirty-one".