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1130203013333 is a prime number
BaseRepresentation
bin10000011100100101010…
…110010110000011010101
311000001020210100211001012
4100130211112112003111
5122004123432411313
62223112540542005
7144440325051002
oct20344526260325
94001223324035
101130203013333
113a6353155a39
1216305a851905
13827682410b4
143c9b887a8a9
151e5ec32bda8
hex107255960d5

1130203013333 has 2 divisors, whose sum is σ = 1130203013334. Its totient is φ = 1130203013332.

The previous prime is 1130203013293. The next prime is 1130203013353. The reversal of 1130203013333 is 3333103020311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 736613660644 + 393589352689 = 858262^2 + 627367^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130203013333 - 212 = 1130203009237 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1130203013299 and 1130203013308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130203013353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565101506666 + 565101506667.

It is an arithmetic number, because the mean of its divisors is an integer number (565101506667).

Almost surely, 21130203013333 is an apocalyptic number.

It is an amenable number.

1130203013333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130203013333 is an equidigital number, since it uses as much as digits as its factorization.

1130203013333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 1130203013333 its reverse (3333103020311), we get a palindrome (4463306033644).

The spelling of 1130203013333 in words is "one trillion, one hundred thirty billion, two hundred three million, thirteen thousand, three hundred thirty-three".