Base | Representation |
---|---|
bin | 11001101100101010011000… |
… | …000010110100011111011110 |
3 | 112211011122012110001102000121 |
4 | 121230222120002310133132 |
5 | 104303211103444144240 |
6 | 1040212452433545154 |
7 | 32543306616511015 |
oct | 3154523002643736 |
9 | 484148173042017 |
10 | 113020320303070 |
11 | 33014715417374 |
12 | 108141187151ba |
13 | 4b0aa0296511b |
14 | 1dca2d9899a7c |
15 | d0edb7d9204a |
hex | 66ca980b47de |
113020320303070 has 64 divisors (see below), whose sum is σ = 211051637379072. Its totient is φ = 43530868800000.
The previous prime is 113020320303067. The next prime is 113020320303071. The reversal of 113020320303070 is 70303023020311.
It is a super-3 number, since 3×1130203203030703 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113020320303071) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 75277015 + ... + 76763725.
It is an arithmetic number, because the mean of its divisors is an integer number (3297681834048).
Almost surely, 2113020320303070 is an apocalyptic number.
113020320303070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113020320303070 is a deficient number, since it is larger than the sum of its proper divisors (98031317076002).
113020320303070 is a wasteful number, since it uses less digits than its factorization.
113020320303070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1487977.
The product of its (nonzero) digits is 2268, while the sum is 25.
Adding to 113020320303070 its reverse (70303023020311), we get a palindrome (183323343323381).
The spelling of 113020320303070 in words is "one hundred thirteen trillion, twenty billion, three hundred twenty million, three hundred three thousand, seventy".
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