Base | Representation |
---|---|
bin | 10101000011010100… |
… | …00110100100001110 |
3 | 1002011122220100001220 |
4 | 22201222012210032 |
5 | 141121314301220 |
6 | 5105255144210 |
7 | 550035202341 |
oct | 124152064416 |
9 | 32148810056 |
10 | 11302103310 |
11 | 487a819553 |
12 | 2235075066 |
13 | 10b16b08c4 |
14 | 793070458 |
15 | 462366540 |
hex | 2a1a8690e |
11302103310 has 32 divisors (see below), whose sum is σ = 27127850400. Its totient is φ = 3013582848.
The previous prime is 11302103261. The next prime is 11302103333. The reversal of 11302103310 is 1330120311.
It is a super-2 number, since 2×113021033102 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 11302103310.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 531034 + ... + 551906.
It is an arithmetic number, because the mean of its divisors is an integer number (847745325).
Almost surely, 211302103310 is an apocalyptic number.
11302103310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11302103310 is an abundant number, since it is smaller than the sum of its proper divisors (15825747090).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11302103310 is a wasteful number, since it uses less digits than its factorization.
11302103310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38932.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11302103310 its reverse (1330120311), we get a palindrome (12632223621).
The spelling of 11302103310 in words is "eleven billion, three hundred two million, one hundred three thousand, three hundred ten".
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