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11302110113 = 71614587159
BaseRepresentation
bin10101000011010100…
…01000001110100001
31002011122220200101212
422201222020032201
5141121320010423
65105255235505
7550035231230
oct124152101641
932148820355
1011302110113
11487a823678
122235078b95
1310b16b3a28
14793072b17
15462368578
hex2a1a883a1

11302110113 has 4 divisors (see below), whose sum is σ = 12916697280. Its totient is φ = 9687522948.

The previous prime is 11302110101. The next prime is 11302110121. The reversal of 11302110113 is 31101120311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11302110113 - 24 = 11302110097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11302113113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 807293573 + ... + 807293586.

It is an arithmetic number, because the mean of its divisors is an integer number (3229174320).

Almost surely, 211302110113 is an apocalyptic number.

It is an amenable number.

11302110113 is a deficient number, since it is larger than the sum of its proper divisors (1614587167).

11302110113 is an equidigital number, since it uses as much as digits as its factorization.

11302110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1614587166.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11302110113 its reverse (31101120311), we get a palindrome (42403230424).

The spelling of 11302110113 in words is "eleven billion, three hundred two million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 7 1614587159 11302110113