Base | Representation |
---|---|
bin | 10000011100100101110… |
… | …100110111000110010101 |
3 | 11000001021100102020112122 |
4 | 100130211310313012111 |
5 | 122004133004404023 |
6 | 2223113424225325 |
7 | 144440453046455 |
oct | 20344564670625 |
9 | 4001240366478 |
10 | 1130211013013 |
11 | 3a635771a245 |
12 | 16306146b245 |
13 | 82769ab2334 |
14 | 3c9b995dd65 |
15 | 1e5ecdac2c8 |
hex | 10725d37195 |
1130211013013 has 2 divisors, whose sum is σ = 1130211013014. Its totient is φ = 1130211013012.
The previous prime is 1130211012989. The next prime is 1130211013027. The reversal of 1130211013013 is 3103101120311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1115087424529 + 15123588484 = 1055977^2 + 122978^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130211013013 - 28 = 1130211012757 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1130211012982 and 1130211013000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130211013313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565105506506 + 565105506507.
It is an arithmetic number, because the mean of its divisors is an integer number (565105506507).
Almost surely, 21130211013013 is an apocalyptic number.
It is an amenable number.
1130211013013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130211013013 is an equidigital number, since it uses as much as digits as its factorization.
1130211013013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1130211013013 its reverse (3103101120311), we get a palindrome (4233312133324).
The spelling of 1130211013013 in words is "one trillion, one hundred thirty billion, two hundred eleven million, thirteen thousand, thirteen".
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