Base | Representation |
---|---|
bin | 110100101000010010… |
… | …1101111010010111111 |
3 | 101210201122100212010021 |
4 | 1221100211233102333 |
5 | 3322431413020111 |
6 | 123530552553011 |
7 | 11110525343056 |
oct | 1512045572277 |
9 | 353648325107 |
10 | 113021220031 |
11 | 43a28594475 |
12 | 19aa26b2767 |
13 | a872400c75 |
14 | 568255139d |
15 | 2e1747dd71 |
hex | 1a5096f4bf |
113021220031 has 4 divisors (see below), whose sum is σ = 113028043912. Its totient is φ = 113014396152.
The previous prime is 113021220007. The next prime is 113021220119. The reversal of 113021220031 is 130022120311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113021220031 - 217 = 113021088959 is a prime.
It is a super-2 number, since 2×1130212200312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113021219987 and 113021220014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113021220731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3387036 + ... + 3420241.
It is an arithmetic number, because the mean of its divisors is an integer number (28257010978).
Almost surely, 2113021220031 is an apocalyptic number.
113021220031 is a deficient number, since it is larger than the sum of its proper divisors (6823881).
113021220031 is an equidigital number, since it uses as much as digits as its factorization.
113021220031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6823880.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 113021220031 its reverse (130022120311), we get a palindrome (243043340342).
The spelling of 113021220031 in words is "one hundred thirteen billion, twenty-one million, two hundred twenty thousand, thirty-one".
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