1130213011 has 4 divisors (see below), whose sum is σ = 1157779224. Its totient is φ = 1102646800.

The previous prime is 1130212997. The next prime is 1130213033. The reversal of 1130213011 is 1103120311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1103120311 = 269 ⋅4100819.

It is a cyclic number.

It is not a de Polignac number, because 1130213011 - 2²⁵ = 1096658579 is a prime.

It is a super-3 number, since 3×1130213011³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130212982 and 1130213000.

It is not an unprimeable number, because it can be changed into a prime (1130213611) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13783045 + ... + 13783126.

It is an arithmetic number, because the mean of its divisors is an integer number (289444806).

Almost surely, 2^1130213011 is an apocalyptic number.

1130213011 is a deficient number, since it is larger than the sum of its proper divisors (27566213).

1130213011 is an equidigital number, since it uses as much as digits as its factorization.

1130213011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27566212.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1130213011 is about 33618.6408261845. The cubic root of 1130213011 is about 1041.6458810089.

Adding to 1130213011 its reverse (1103120311), we get a palindrome (2233333322).

The spelling of 1130213011 in words is "one billion, one hundred thirty million, two hundred thirteen thousand, eleven".