Base | Representation |
---|---|
bin | 110100101000010100… |
… | …0110000001100100011 |
3 | 101210201200211222221211 |
4 | 1221100220300030203 |
5 | 3322432113311042 |
6 | 123531021530551 |
7 | 11110535143444 |
oct | 1512050601443 |
9 | 353650758854 |
10 | 113022010147 |
11 | 43a28a84062 |
12 | 19aa2a13a57 |
13 | a8726197a7 |
14 | 56826b92cb |
15 | 2e17588017 |
hex | 1a50a30323 |
113022010147 has 2 divisors, whose sum is σ = 113022010148. Its totient is φ = 113022010146.
The previous prime is 113022010117. The next prime is 113022010181. The reversal of 113022010147 is 741010220311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113022010147 is a prime.
It is not a weakly prime, because it can be changed into another prime (113022010117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56511005073 + 56511005074.
It is an arithmetic number, because the mean of its divisors is an integer number (56511005074).
Almost surely, 2113022010147 is an apocalyptic number.
113022010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
113022010147 is an equidigital number, since it uses as much as digits as its factorization.
113022010147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 113022010147 its reverse (741010220311), we get a palindrome (854032230458).
The spelling of 113022010147 in words is "one hundred thirteen billion, twenty-two million, ten thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •