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11302213231 = 17683639157
BaseRepresentation
bin10101000011010101…
…00001011001101111
31002011200002220212001
422201222201121233
5141121331310411
65105301353131
7550036140661
oct124152413157
932150086761
1011302213231
11487a8940a1
1222351087a7
1310b171b94a
1479309c531
15462388dc1
hex2a1aa166f

11302213231 has 4 divisors (see below), whose sum is σ = 11302870072. Its totient is φ = 11301556392.

The previous prime is 11302213211. The next prime is 11302213243. The reversal of 11302213231 is 13231220311.

11302213231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13231220311 = 61216905251.

It is a cyclic number.

It is not a de Polignac number, because 11302213231 - 229 = 10765342319 is a prime.

It is a super-2 number, since 2×113022132312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11302213199 and 11302213208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11302213211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 301896 + ... + 337261.

It is an arithmetic number, because the mean of its divisors is an integer number (2825717518).

Almost surely, 211302213231 is an apocalyptic number.

11302213231 is a deficient number, since it is larger than the sum of its proper divisors (656841).

11302213231 is an equidigital number, since it uses as much as digits as its factorization.

11302213231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656840.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11302213231 its reverse (13231220311), we get a palindrome (24533433542).

It can be divided in two parts, 113022 and 13231, that added together give a triangular number (126253 = T502).

The spelling of 11302213231 in words is "eleven billion, three hundred two million, two hundred thirteen thousand, two hundred thirty-one".

Divisors: 1 17683 639157 11302213231