1130231200013 has 4 divisors (see below), whose sum is σ = 1130373143328. Its totient is φ = 1130089256700.

The previous prime is 1130231199971. The next prime is 1130231200073. The reversal of 1130231200013 is 3100021320311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1130231200013 is a prime.

It is a super-2 number, since 2×1130231200013² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130231199964 and 1130231200000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130231200073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70959713 + ... + 70975638.

It is an arithmetic number, because the mean of its divisors is an integer number (282593285832).

Almost surely, 2^{1130231200013} is an apocalyptic number.

It is an amenable number.

1130231200013 is a deficient number, since it is larger than the sum of its proper divisors (141943315).

1130231200013 is an equidigital number, since it uses as much as digits as its factorization.

1130231200013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141943314.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1130231200013 its reverse (3100021320311), we get a palindrome (4230252520324).

The spelling of 1130231200013 in words is "one trillion, one hundred thirty billion, two hundred thirty-one million, two hundred thousand, thirteen".