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1130302001011 is a prime number
BaseRepresentation
bin10000011100101011001…
…111111100111101110011
311000001111200121220121111
4100130223033330331303
5122004324303013021
62223130434334151
7144442636325551
oct20345317747563
94001450556544
101130302001011
113a63a4015937
12163087a2a357
13827828bbba1
143c9c7a86bd1
151e605d818e1
hex1072b3fcf73

1130302001011 has 2 divisors, whose sum is σ = 1130302001012. Its totient is φ = 1130302001010.

The previous prime is 1130302001009. The next prime is 1130302001027. The reversal of 1130302001011 is 1101002030311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1130302001011 - 21 = 1130302001009 is a prime.

It is a super-2 number, since 2×11303020010112 (a number of 25 digits) contains 22 as substring.

Together with 1130302001009, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1130302000982 and 1130302001000.

It is not a weakly prime, because it can be changed into another prime (1130302001111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565151000505 + 565151000506.

It is an arithmetic number, because the mean of its divisors is an integer number (565151000506).

Almost surely, 21130302001011 is an apocalyptic number.

1130302001011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130302001011 is an equidigital number, since it uses as much as digits as its factorization.

1130302001011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1130302001011 its reverse (1101002030311), we get a palindrome (2231304031322).

The spelling of 1130302001011 in words is "one trillion, one hundred thirty billion, three hundred two million, one thousand, eleven".