11303121133 has 4 divisors (see below), whose sum is σ = 11543613120. Its totient is φ = 11062629148.

The previous prime is 11303121097. The next prime is 11303121139. The reversal of 11303121133 is 33112130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33112130311 = 13 ⋅2547086947.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11303121133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11303121133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11303121139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120245923 + ... + 120246016.

It is an arithmetic number, because the mean of its divisors is an integer number (2885903280).

Almost surely, 2^11303121133 is an apocalyptic number.

It is an amenable number.

11303121133 is a deficient number, since it is larger than the sum of its proper divisors (240491987).

11303121133 is an equidigital number, since it uses as much as digits as its factorization.

11303121133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240491986.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11303121133 its reverse (33112130311), we get a palindrome (44415251444).

The spelling of 11303121133 in words is "eleven billion, three hundred three million, one hundred twenty-one thousand, one hundred thirty-three".