1130312131133 has 4 divisors (see below), whose sum is σ = 1156598459808. Its totient is φ = 1104025802460.

The previous prime is 1130312131127. The next prime is 1130312131159. The reversal of 1130312131133 is 3311312130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130312131133 - 2¹² = 1130312127037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130312131099 and 1130312131108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130312136133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13143164273 + ... + 13143164358.

It is an arithmetic number, because the mean of its divisors is an integer number (289149614952).

Almost surely, 2^{1130312131133} is an apocalyptic number.

It is an amenable number.

1130312131133 is a deficient number, since it is larger than the sum of its proper divisors (26286328675).

1130312131133 is an equidigital number, since it uses as much as digits as its factorization.

1130312131133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26286328674.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1130312131133 its reverse (3311312130311), we get a palindrome (4441624261444).

The spelling of 1130312131133 in words is "one trillion, one hundred thirty billion, three hundred twelve million, one hundred thirty-one thousand, one hundred thirty-three".