Base | Representation |
---|---|
bin | 110100101000100110… |
… | …0001100010011101011 |
3 | 101210202100022222200201 |
4 | 1221101030030103223 |
5 | 3322442003102311 |
6 | 123531553013031 |
7 | 11111010125515 |
oct | 1512114142353 |
9 | 353670288621 |
10 | 113031300331 |
11 | 43a332499a4 |
12 | 19aa5b54177 |
13 | a874520241 |
14 | 5683a16bb5 |
15 | 2e182c09c1 |
hex | 1a5130c4eb |
113031300331 has 2 divisors, whose sum is σ = 113031300332. Its totient is φ = 113031300330.
The previous prime is 113031300293. The next prime is 113031300377. The reversal of 113031300331 is 133003130311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113031300331 - 27 = 113031300203 is a prime.
It is a super-2 number, since 2×1130313003312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113031300299 and 113031300308.
It is not a weakly prime, because it can be changed into another prime (113031306331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56515650165 + 56515650166.
It is an arithmetic number, because the mean of its divisors is an integer number (56515650166).
Almost surely, 2113031300331 is an apocalyptic number.
113031300331 is a deficient number, since it is larger than the sum of its proper divisors (1).
113031300331 is an equidigital number, since it uses as much as digits as its factorization.
113031300331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 113031300331 its reverse (133003130311), we get a palindrome (246034430642).
The spelling of 113031300331 in words is "one hundred thirteen billion, thirty-one million, three hundred thousand, three hundred thirty-one".
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