Base | Representation |
---|---|
bin | 11001101100110101010000… |
… | …111000001011001110101011 |
3 | 112211012202101012121010210201 |
4 | 121230311100320023032223 |
5 | 104303404024333412141 |
6 | 1040222104503053031 |
7 | 32544202415665303 |
oct | 3154652070131653 |
9 | 484182335533721 |
10 | 113032011232171 |
11 | 33019674669449 |
12 | 1081643ba41177 |
13 | 4b0bb46a74155 |
14 | 1dcaac8422603 |
15 | d1034e411031 |
hex | 66cd50e0b3ab |
113032011232171 has 2 divisors, whose sum is σ = 113032011232172. Its totient is φ = 113032011232170.
The previous prime is 113032011232169. The next prime is 113032011232201. The reversal of 113032011232171 is 171232110230311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113032011232171 - 21 = 113032011232169 is a prime.
It is a super-2 number, since 2×1130320112321712 (a number of 29 digits) contains 22 as substring.
Together with 113032011232169, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (113032011238171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56516005616085 + 56516005616086.
It is an arithmetic number, because the mean of its divisors is an integer number (56516005616086).
Almost surely, 2113032011232171 is an apocalyptic number.
113032011232171 is a deficient number, since it is larger than the sum of its proper divisors (1).
113032011232171 is an equidigital number, since it uses as much as digits as its factorization.
113032011232171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 113032011232171 its reverse (171232110230311), we get a palindrome (284264121462482).
The spelling of 113032011232171 in words is "one hundred thirteen trillion, thirty-two billion, eleven million, two hundred thirty-two thousand, one hundred seventy-one".
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