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113032296437 is a prime number
BaseRepresentation
bin110100101000100111…
…1111111011111110101
3101210202102012121002112
41221101033333133311
53322442231441222
6123532030220405
711111021444564
oct1512117773765
9353672177075
10113032296437
1143a3386a325
1219aa6354705
13a8747ab758
145683bd5bdb
152e1841abe2
hex1a513ff7f5

113032296437 has 2 divisors, whose sum is σ = 113032296438. Its totient is φ = 113032296436.

The previous prime is 113032296383. The next prime is 113032296449. The reversal of 113032296437 is 734692230311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112959176836 + 73119601 = 336094^2 + 8551^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113032296437 is a prime.

It is a super-3 number, since 3×1130322964373 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113032296394 and 113032296403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113032296337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56516148218 + 56516148219.

It is an arithmetic number, because the mean of its divisors is an integer number (56516148219).

Almost surely, 2113032296437 is an apocalyptic number.

It is an amenable number.

113032296437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113032296437 is an equidigital number, since it uses as much as digits as its factorization.

113032296437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 163296, while the sum is 41.

The spelling of 113032296437 in words is "one hundred thirteen billion, thirty-two million, two hundred ninety-six thousand, four hundred thirty-seven".