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11304132011 is a prime number
BaseRepresentation
bin10101000011100011…
…10101110110101011
31002011210201101220222
422201301311312223
5141122324211021
65105410440255
7550061352044
oct124161656653
932153641828
1011304132011
114880984767
12223589308b
1310b1c41113
1479343b8cb
154626176ab
hex2a1c75dab

11304132011 has 2 divisors, whose sum is σ = 11304132012. Its totient is φ = 11304132010.

The previous prime is 11304132001. The next prime is 11304132019. The reversal of 11304132011 is 11023140311.

It is a strong prime.

It is an emirp because it is prime and its reverse (11023140311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11304132011 - 218 = 11303869867 is a prime.

It is a super-3 number, since 3×113041320113 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11304132019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652066005 + 5652066006.

It is an arithmetic number, because the mean of its divisors is an integer number (5652066006).

Almost surely, 211304132011 is an apocalyptic number.

11304132011 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304132011 is an equidigital number, since it uses as much as digits as its factorization.

11304132011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11304132011 its reverse (11023140311), we get a palindrome (22327272322).

The spelling of 11304132011 in words is "eleven billion, three hundred four million, one hundred thirty-two thousand, eleven".