Base | Representation |
---|---|
bin | 110100101001001110… |
… | …1000111011011010101 |
3 | 101210210211020202101100 |
4 | 1221102131013123111 |
5 | 3323012420422010 |
6 | 123534031420313 |
7 | 11111355341124 |
oct | 1512235073325 |
9 | 353724222340 |
10 | 113052514005 |
11 | 43a44219062 |
12 | 19ab1084699 |
13 | a878a39c02 |
14 | 5686779abb |
15 | 2e1a0b12c0 |
hex | 1a527476d5 |
113052514005 has 12 divisors (see below), whose sum is σ = 195957691020. Its totient is φ = 60294674112.
The previous prime is 113052513997. The next prime is 113052514007. The reversal of 113052514005 is 500415250311.
113052514005 is a `hidden beast` number, since 1 + 1 + 3 + 0 + 5 + 251 + 400 + 5 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 21726465201 + 91326048804 = 147399^2 + 302202^2 .
It is not a de Polignac number, because 113052514005 - 23 = 113052513997 is a prime.
It is a super-2 number, since 2×1130525140052 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 113052514005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113052514007) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1256139000 + ... + 1256139089.
It is an arithmetic number, because the mean of its divisors is an integer number (16329807585).
Almost surely, 2113052514005 is an apocalyptic number.
113052514005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113052514005 is a deficient number, since it is larger than the sum of its proper divisors (82905177015).
113052514005 is a wasteful number, since it uses less digits than its factorization.
113052514005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2512278100 (or 2512278097 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 113052514005 its reverse (500415250311), we get a palindrome (613467764316).
The spelling of 113052514005 in words is "one hundred thirteen billion, fifty-two million, five hundred fourteen thousand, five".
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