Base | Representation |
---|---|
bin | 10000011101000001111… |
… | …111100111000110001111 |
3 | 11000002111021122210112221 |
4 | 100131001333213012033 |
5 | 122011114444434403 |
6 | 2223232345240211 |
7 | 144455251652131 |
oct | 20350177470617 |
9 | 4002437583487 |
10 | 1130683593103 |
11 | 3a657a4586a9 |
12 | 163173793067 |
13 | 8281398691c |
14 | 3ca22619051 |
15 | 1e62960adbd |
hex | 10741fe718f |
1130683593103 has 2 divisors, whose sum is σ = 1130683593104. Its totient is φ = 1130683593102.
The previous prime is 1130683593101. The next prime is 1130683593203. The reversal of 1130683593103 is 3013953860311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1130683593103 - 21 = 1130683593101 is a prime.
Together with 1130683593101, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1130683593103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130683593101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565341796551 + 565341796552.
It is an arithmetic number, because the mean of its divisors is an integer number (565341796552).
Almost surely, 21130683593103 is an apocalyptic number.
1130683593103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130683593103 is an equidigital number, since it uses as much as digits as its factorization.
1130683593103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 43.
The spelling of 1130683593103 in words is "one trillion, one hundred thirty billion, six hundred eighty-three million, five hundred ninety-three thousand, one hundred three".
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