11310000001 has 4 divisors (see below), whose sum is σ = 11314055104. Its totient is φ = 11305944900.

The previous prime is 11309999999. The next prime is 11310000007. The reversal of 11310000001 is 10000001311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10000001311 = 41 ⋅243902471.

It is a cyclic number.

It is not a de Polignac number, because 11310000001 - 2¹ = 11309999999 is a prime.

It is a super-2 number, since 2×11310000001² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11310000007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2023365 + ... + 2028946.

It is an arithmetic number, because the mean of its divisors is an integer number (2828513776).

Almost surely, 2^11310000001 is an apocalyptic number.

It is an amenable number.

11310000001 is a deficient number, since it is larger than the sum of its proper divisors (4055103).

11310000001 is an equidigital number, since it uses as much as digits as its factorization.

11310000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4055102.

The product of its (nonzero) digits is 3, while the sum is 7.

Adding to 11310000001 its reverse (10000001311), we get a palindrome (21310001312).

The spelling of 11310000001 in words is "eleven billion, three hundred ten million, one", and thus it is an aban number.