Base | Representation |
---|---|
bin | 10101000100010000… |
… | …01111000001111111 |
3 | 1002012012202122110012 |
4 | 22202020033001333 |
5 | 141130330033203 |
6 | 5110140333435 |
7 | 550162301435 |
oct | 124210170177 |
9 | 32165678405 |
10 | 11310002303 |
11 | 4884224146 |
12 | 223784427b |
13 | 10b3218072 |
14 | 794128d55 |
15 | 462dc6bd8 |
hex | 2a220f07f |
11310002303 has 2 divisors, whose sum is σ = 11310002304. Its totient is φ = 11310002302.
The previous prime is 11310002299. The next prime is 11310002317. The reversal of 11310002303 is 30320001311.
It is an a-pointer prime, because the next prime (11310002317) can be obtained adding 11310002303 to its sum of digits (14).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11310002303 - 22 = 11310002299 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310002323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655001151 + 5655001152.
It is an arithmetic number, because the mean of its divisors is an integer number (5655001152).
Almost surely, 211310002303 is an apocalyptic number.
11310002303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310002303 is an equidigital number, since it uses as much as digits as its factorization.
11310002303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 11310002303 its reverse (30320001311), we get a palindrome (41630003614).
The spelling of 11310002303 in words is "eleven billion, three hundred ten million, two thousand, three hundred three".
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