Base | Representation |
---|---|
bin | 10101000100010000… |
… | …10001001010001111 |
3 | 1002012012210002102011 |
4 | 22202020101022033 |
5 | 141130330323043 |
6 | 5110140442051 |
7 | 550162336033 |
oct | 124210211217 |
9 | 32165702364 |
10 | 11310011023 |
11 | 488422a753 |
12 | 2237849327 |
13 | 10b321c01c |
14 | 79412c1c3 |
15 | 462dc959d |
hex | 2a221128f |
11310011023 has 4 divisors (see below), whose sum is σ = 11319492528. Its totient is φ = 11300529520.
The previous prime is 11310010963. The next prime is 11310011029. The reversal of 11310011023 is 32011001311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11310011023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11310010994 and 11310011012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310011029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4738963 + ... + 4741348.
It is an arithmetic number, because the mean of its divisors is an integer number (2829873132).
Almost surely, 211310011023 is an apocalyptic number.
11310011023 is a deficient number, since it is larger than the sum of its proper divisors (9481505).
11310011023 is an equidigital number, since it uses as much as digits as its factorization.
11310011023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9481504.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11310011023 its reverse (32011001311), we get a palindrome (43321012334).
The spelling of 11310011023 in words is "eleven billion, three hundred ten million, eleven thousand, twenty-three".
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