Base | Representation |
---|---|
bin | 10000011101010100111… |
… | …010111011100100111011 |
3 | 11000010022102011111220121 |
4 | 100131110322323210323 |
5 | 122012242242231441 |
6 | 2223324051234111 |
7 | 144466156004404 |
oct | 20352472734473 |
9 | 4003272144817 |
10 | 1131001133371 |
11 | 3a672272237a |
12 | 163241ba8937 |
13 | 828646b6385 |
14 | 3ca528769ab |
15 | 1e647431dd1 |
hex | 10754ebb93b |
1131001133371 has 2 divisors, whose sum is σ = 1131001133372. Its totient is φ = 1131001133370.
The previous prime is 1131001133321. The next prime is 1131001133393. The reversal of 1131001133371 is 1733311001311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1733311001311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131001133371 - 227 = 1130866915643 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131001133321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565500566685 + 565500566686.
It is an arithmetic number, because the mean of its divisors is an integer number (565500566686).
Almost surely, 21131001133371 is an apocalyptic number.
1131001133371 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131001133371 is an equidigital number, since it uses as much as digits as its factorization.
1131001133371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 567, while the sum is 25.
Adding to 1131001133371 its reverse (1733311001311), we get a palindrome (2864312134682).
The spelling of 1131001133371 in words is "one trillion, one hundred thirty-one billion, one million, one hundred thirty-three thousand, three hundred seventy-one".
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