Base | Representation |
---|---|
bin | 10000011101010100111… |
… | …011010011011111000111 |
3 | 11000010022102100111020201 |
4 | 100131110323103133013 |
5 | 122012242303400203 |
6 | 2223324053311331 |
7 | 144466156563046 |
oct | 20352473233707 |
9 | 4003272314221 |
10 | 1131001231303 |
11 | 3a6722789a09 |
12 | 163242035547 |
13 | 8286471bb18 |
14 | 3ca528a055d |
15 | 1e647450e1d |
hex | 10754ed37c7 |
1131001231303 has 2 divisors, whose sum is σ = 1131001231304. Its totient is φ = 1131001231302.
The previous prime is 1131001231291. The next prime is 1131001231309. The reversal of 1131001231303 is 3031321001311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131001231303 - 229 = 1130464360391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131001231309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565500615651 + 565500615652.
It is an arithmetic number, because the mean of its divisors is an integer number (565500615652).
Almost surely, 21131001231303 is an apocalyptic number.
1131001231303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131001231303 is an equidigital number, since it uses as much as digits as its factorization.
1131001231303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1131001231303 its reverse (3031321001311), we get a palindrome (4162322232614).
The spelling of 1131001231303 in words is "one trillion, one hundred thirty-one billion, one million, two hundred thirty-one thousand, three hundred three".
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