Base | Representation |
---|---|
bin | 110100101010101001… |
… | …1100001100001011111 |
3 | 101210221011020010002222 |
4 | 1221111103201201133 |
5 | 3323112141043403 |
6 | 123542500335555 |
7 | 11112505644434 |
oct | 1512523414137 |
9 | 353834203088 |
10 | 113100331103 |
11 | 43a69208821 |
12 | 19b050a45bb |
13 | a88590c856 |
14 | 568cc65b8b |
15 | 2e1e3a9338 |
hex | 1a554e185f |
113100331103 has 2 divisors, whose sum is σ = 113100331104. Its totient is φ = 113100331102.
The previous prime is 113100331037. The next prime is 113100331109. The reversal of 113100331103 is 301133001311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113100331103 - 218 = 113100068959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113100331109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550165551 + 56550165552.
It is an arithmetic number, because the mean of its divisors is an integer number (56550165552).
Almost surely, 2113100331103 is an apocalyptic number.
113100331103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113100331103 is an equidigital number, since it uses as much as digits as its factorization.
113100331103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 113100331103 its reverse (301133001311), we get a palindrome (414233332414).
The spelling of 113100331103 in words is "one hundred thirteen billion, one hundred million, three hundred thirty-one thousand, one hundred three".
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