Base | Representation |
---|---|
bin | 1010010010010101011010… |
… | …1011000111010011000111 |
3 | 1111001020100112012221221002 |
4 | 2210211112223013103013 |
5 | 2440301042334024111 |
6 | 40015442315443515 |
7 | 2245061616364535 |
oct | 244452653072307 |
9 | 44036315187832 |
10 | 11310103033031 |
11 | 3670651343490 |
12 | 1327b8275659b |
13 | 6406cc3a62ca |
14 | 2b15aa3bb155 |
15 | 149305cc963b |
hex | a4956ac74c7 |
11310103033031 has 8 divisors (see below), whose sum is σ = 12400925155344. Its totient is φ = 10229719400320.
The previous prime is 11310103032997. The next prime is 11310103033037. The reversal of 11310103033031 is 13033030101311.
11310103033031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11310103033031 is a prime.
It is a super-2 number, since 2×113101030330312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11310103032994 and 11310103033012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310103033037) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2609620130 + ... + 2609624463.
It is an arithmetic number, because the mean of its divisors is an integer number (1550115644418).
Almost surely, 211310103033031 is an apocalyptic number.
11310103033031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11310103033031 is a deficient number, since it is larger than the sum of its proper divisors (1090822122313).
11310103033031 is a wasteful number, since it uses less digits than its factorization.
11310103033031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5219244801.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 11310103033031 its reverse (13033030101311), we get a palindrome (24343133134342).
The spelling of 11310103033031 in words is "eleven trillion, three hundred ten billion, one hundred three million, thirty-three thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •