11310112117 has 2 divisors, whose sum is σ = 11310112118. Its totient is φ = 11310112116.

The previous prime is 11310112111. The next prime is 11310112123. The reversal of 11310112117 is 71121101311.

It is a balanced prime because it is at equal distance from previous prime (11310112111) and next prime (11310112123).

It can be written as a sum of positive squares in only one way, i.e., 7527124081 + 3782988036 = 86759^2 + 61506^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310112117 - 2¹⁹ = 11309587829 is a prime.

It is a super-2 number, since 2×11310112117² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11310112094 and 11310112103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310112111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655056058 + 5655056059.

It is an arithmetic number, because the mean of its divisors is an integer number (5655056059).

Almost surely, 2^11310112117 is an apocalyptic number.

It is an amenable number.

11310112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310112117 is an equidigital number, since it uses as much as digits as its factorization.

11310112117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 19.

Adding to 11310112117 its reverse (71121101311), we get a palindrome (82431213428).

The spelling of 11310112117 in words is "eleven billion, three hundred ten million, one hundred twelve thousand, one hundred seventeen".