1131011311 has 2 divisors, whose sum is σ = 1131011312. Its totient is φ = 1131011310.

The previous prime is 1131011239. The next prime is 1131011317. The reversal of 1131011311 is 1131101311.

It is a strong prime.

It is an emirp because it is prime and its reverse (1131101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131011311 - 2²³ = 1122622703 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131011291 and 1131011300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131011317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565505655 + 565505656.

It is an arithmetic number, because the mean of its divisors is an integer number (565505656).

Almost surely, 2^1131011311 is an apocalyptic number.

1131011311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131011311 is an equidigital number, since it uses as much as digits as its factorization.

1131011311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

The square root of 1131011311 is about 33630.5116077648. The cubic root of 1131011311 is about 1041.8910708372.

Adding to 1131011311 its reverse (1131101311), we get a palindrome (2262112622).

Subtracting 1131011311 from its reverse (1131101311), we obtain a square (90000 = 300²).

The spelling of 1131011311 in words is "one billion, one hundred thirty-one million, eleven thousand, three hundred eleven".