1131011313133 has 4 divisors (see below), whose sum is σ = 1218012183388. Its totient is φ = 1044010442880.

The previous prime is 1131011313127. The next prime is 1131011313169. The reversal of 1131011313133 is 3313131101311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 298834968964 + 832176344169 = 546658^2 + 912237^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131011313133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131011313193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43500435108 + ... + 43500435133.

It is an arithmetic number, because the mean of its divisors is an integer number (304503045847).

Almost surely, 2^{1131011313133} is an apocalyptic number.

1131011313133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1131011313133 is a deficient number, since it is larger than the sum of its proper divisors (87000870255).

1131011313133 is an equidigital number, since it uses as much as digits as its factorization.

1131011313133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87000870254.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 1131011313133 its reverse (3313131101311), we get a palindrome (4444142414444).

The spelling of 1131011313133 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirteen thousand, one hundred thirty-three".