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113101210133 is a prime number
BaseRepresentation
bin110100101010101011…
…0111000001000010101
3101210221012212202220122
41221111112320020111
53323112402211013
6123542531241325
711112516265262
oct1512526701025
9353835782818
10113101210133
1143a6975919a
1219b05449245
13a885b599a2
14568d014269
152e1e4cea08
hex1a555b8215

113101210133 has 2 divisors, whose sum is σ = 113101210134. Its totient is φ = 113101210132.

The previous prime is 113101210109. The next prime is 113101210147. The reversal of 113101210133 is 331012101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89160765604 + 23940444529 = 298598^2 + 154727^2 .

It is a cyclic number.

It is not a de Polignac number, because 113101210133 - 224 = 113084432917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113101210153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550605066 + 56550605067.

It is an arithmetic number, because the mean of its divisors is an integer number (56550605067).

Almost surely, 2113101210133 is an apocalyptic number.

It is an amenable number.

113101210133 is a deficient number, since it is larger than the sum of its proper divisors (1).

113101210133 is an equidigital number, since it uses as much as digits as its factorization.

113101210133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113101210133 its reverse (331012101311), we get a palindrome (444113311444).

The spelling of 113101210133 in words is "one hundred thirteen billion, one hundred one million, two hundred ten thousand, one hundred thirty-three".