Base | Representation |
---|---|
bin | 1010010010010101100001… |
… | …0010010111100001001111 |
3 | 1111001020102102011010020122 |
4 | 2210211120102113201033 |
5 | 2440301121301202203 |
6 | 40015445123535155 |
7 | 2245062365430056 |
oct | 244453022274117 |
9 | 44036372133218 |
10 | 11310130100303 |
11 | 3670665650531 |
12 | 1327b8b82a4bb |
13 | 640704b92448 |
14 | 2b15adc2539d |
15 | 149308374538 |
hex | a495849784f |
11310130100303 has 4 divisors (see below), whose sum is σ = 11310150546408. Its totient is φ = 11310109654200.
The previous prime is 11310130100257. The next prime is 11310130100341. The reversal of 11310130100303 is 30300103101311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11310130100303 - 212 = 11310130096207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310130100603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9369548 + ... + 10507553.
It is an arithmetic number, because the mean of its divisors is an integer number (2827537636602).
Almost surely, 211310130100303 is an apocalyptic number.
11310130100303 is a deficient number, since it is larger than the sum of its proper divisors (20446105).
11310130100303 is an equidigital number, since it uses as much as digits as its factorization.
11310130100303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20446104.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11310130100303 its reverse (30300103101311), we get a palindrome (41610233201614).
The spelling of 11310130100303 in words is "eleven trillion, three hundred ten billion, one hundred thirty million, one hundred thousand, three hundred three".
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