11310133130 has 8 divisors (see below), whose sum is σ = 20358239652. Its totient is φ = 4524053248.

The previous prime is 11310133129. The next prime is 11310133147. The reversal of 11310133130 is 3133101311.

It can be written as a sum of positive squares in 2 ways, for example, as 10050664009 + 1259469121 = 100253^2 + 35489^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×11310133130² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11310133099 and 11310133108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565506647 + ... + 565506666.

Almost surely, 2^11310133130 is an apocalyptic number.

11310133130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11310133130 is a deficient number, since it is larger than the sum of its proper divisors (9048106522).

11310133130 is a wasteful number, since it uses less digits than its factorization.

11310133130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1131013320.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11310133130 its reverse (3133101311), we get a palindrome (14443234441).

The spelling of 11310133130 in words is "eleven billion, three hundred ten million, one hundred thirty-three thousand, one hundred thirty".