Base | Representation |
---|---|
bin | 1010010010010101110010… |
… | …0010000001010000011011 |
3 | 1111001020121101011001201101 |
4 | 2210211130202001100123 |
5 | 2440301243013443113 |
6 | 40015500150132231 |
7 | 2245064221632136 |
oct | 244453442012033 |
9 | 44036541131641 |
10 | 11310201312283 |
11 | 36706a186a105 |
12 | 1327bab651077 |
13 | 640716866803 |
14 | 2b15b948121d |
15 | 14930e73e2dd |
hex | a495c88141b |
11310201312283 has 2 divisors, whose sum is σ = 11310201312284. Its totient is φ = 11310201312282.
The previous prime is 11310201312253. The next prime is 11310201312329. The reversal of 11310201312283 is 38221310201311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11310201312283 - 213 = 11310201304091 is a prime.
It is not a weakly prime, because it can be changed into another prime (11310201312233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655100656141 + 5655100656142.
It is an arithmetic number, because the mean of its divisors is an integer number (5655100656142).
Almost surely, 211310201312283 is an apocalyptic number.
11310201312283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310201312283 is an equidigital number, since it uses as much as digits as its factorization.
11310201312283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 11310201312283 its reverse (38221310201311), we get a palindrome (49531511513594).
The spelling of 11310201312283 in words is "eleven trillion, three hundred ten billion, two hundred one million, three hundred twelve thousand, two hundred eighty-three".
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