Base | Representation |
---|---|
bin | 1010010010010101110010… |
… | …0010000001010001001001 |
3 | 1111001020121101011001210002 |
4 | 2210211130202001101021 |
5 | 2440301243013443304 |
6 | 40015500150132345 |
7 | 2245064221632233 |
oct | 244453442012111 |
9 | 44036541131702 |
10 | 11310201312329 |
11 | 36706a186a147 |
12 | 1327bab6510b5 |
13 | 64071686683a |
14 | 2b15b9481253 |
15 | 14930e73e31e |
hex | a495c881449 |
11310201312329 has 2 divisors, whose sum is σ = 11310201312330. Its totient is φ = 11310201312328.
The previous prime is 11310201312283. The next prime is 11310201312331. The reversal of 11310201312329 is 92321310201311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9079838278729 + 2230363033600 = 3013277^2 + 1493440^2 .
It is a cyclic number.
It is not a de Polignac number, because 11310201312329 - 212 = 11310201308233 is a prime.
Together with 11310201312331, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11310201312829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655100656164 + 5655100656165.
It is an arithmetic number, because the mean of its divisors is an integer number (5655100656165).
Almost surely, 211310201312329 is an apocalyptic number.
It is an amenable number.
11310201312329 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310201312329 is an equidigital number, since it uses as much as digits as its factorization.
11310201312329 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 11310201312329 in words is "eleven trillion, three hundred ten billion, two hundred one million, three hundred twelve thousand, three hundred twenty-nine".
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