1131021403 has 2 divisors, whose sum is σ = 1131021404. Its totient is φ = 1131021402.

The previous prime is 1131021349. The next prime is 1131021421. The reversal of 1131021403 is 3041201311.

It is a strong prime.

It is an emirp because it is prime and its reverse (3041201311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131021403 - 2²⁵ = 1097466971 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131025403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565510701 + 565510702.

It is an arithmetic number, because the mean of its divisors is an integer number (565510702).

Almost surely, 2^1131021403 is an apocalyptic number.

1131021403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131021403 is an equidigital number, since it uses as much as digits as its factorization.

1131021403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1131021403 is about 33630.6616497505. The cubic root of 1131021403 is about 1041.8941697551.

Adding to 1131021403 its reverse (3041201311), we get a palindrome (4172222714).

The spelling of 1131021403 in words is "one billion, one hundred thirty-one million, twenty-one thousand, four hundred three".