1131022141133 has 2 divisors, whose sum is σ = 1131022141134. Its totient is φ = 1131022141132.

The previous prime is 1131022141087. The next prime is 1131022141187. The reversal of 1131022141133 is 3311412201311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 922133837284 + 208888303849 = 960278^2 + 457043^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131022141133 - 2¹⁰ = 1131022140109 is a prime.

It is a super-3 number, since 3×1131022141133³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1131022141099 and 1131022141108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131022941133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565511070566 + 565511070567.

It is an arithmetic number, because the mean of its divisors is an integer number (565511070567).

Almost surely, 2^{1131022141133} is an apocalyptic number.

It is an amenable number.

1131022141133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131022141133 is an equidigital number, since it uses as much as digits as its factorization.

1131022141133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1131022141133 its reverse (3311412201311), we get a palindrome (4442434342444).

The spelling of 1131022141133 in words is "one trillion, one hundred thirty-one billion, twenty-two million, one hundred forty-one thousand, one hundred thirty-three".