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113102330111 = 787143713253
BaseRepresentation
bin110100101010101101…
…1001001100011111111
3101210221021222200020022
41221111123021203333
53323113144030421
6123543011242355
711112531641441
oct1512533114377
9353837880208
10113102330111
1143a6a3536a1
1219b058a93bb
13a88615c6b4
14568d226491
152e1e6517ab
hex1a556c98ff

113102330111 has 4 divisors (see below), whose sum is σ = 113246044152. Its totient is φ = 112958616072.

The previous prime is 113102330083. The next prime is 113102330113. The reversal of 113102330111 is 111033201311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113102330111 - 222 = 113098135807 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113102330111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113102330113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71855840 + ... + 71857413.

It is an arithmetic number, because the mean of its divisors is an integer number (28311511038).

Almost surely, 2113102330111 is an apocalyptic number.

113102330111 is a deficient number, since it is larger than the sum of its proper divisors (143714041).

113102330111 is an equidigital number, since it uses as much as digits as its factorization.

113102330111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143714040.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113102330111 its reverse (111033201311), we get a palindrome (224135531422).

The spelling of 113102330111 in words is "one hundred thirteen billion, one hundred two million, three hundred thirty thousand, one hundred eleven".

Divisors: 1 787 143713253 113102330111