Search a number
-
+
113103020 = 22543113121
BaseRepresentation
bin1101011110111…
…01000010101100
321212211020011202
412233131002230
5212423244040
615120105032
72542234262
oct657350254
9255736152
10113103020
1158930a78
1231a65178
131a580884
1411042432
159de2015
hex6bdd0ac

113103020 has 24 divisors (see below), whose sum is σ = 238085568. Its totient is φ = 45132800.

The previous prime is 113103013. The next prime is 113103037. The reversal of 113103020 is 20301311.

113103020 = 16622 + 16632 + ... + 17012.

It is a junction number, because it is equal to n+sod(n) for n = 113102992 and 113103010.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2060 + ... + 15180.

It is an arithmetic number, because the mean of its divisors is an integer number (9920232).

Almost surely, 2113103020 is an apocalyptic number.

113103020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113103020 is an abundant number, since it is smaller than the sum of its proper divisors (124982548).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113103020 is a wasteful number, since it uses less digits than its factorization.

113103020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13561 (or 13559 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 113103020 is about 10634.9903620079. The cubic root of 113103020 is about 483.6056882239.

Adding to 113103020 its reverse (20301311), we get a palindrome (133404331).

The spelling of 113103020 in words is "one hundred thirteen million, one hundred three thousand, twenty".

Divisors: 1 2 4 5 10 20 431 862 1724 2155 4310 8620 13121 26242 52484 65605 131210 262420 5655151 11310302 22620604 28275755 56551510 113103020