Base | Representation |
---|---|
bin | 10101000100010010… |
… | …11001000011111111 |
3 | 1002012020100001102000 |
4 | 22202021121003333 |
5 | 141130414234120 |
6 | 5110151033343 |
7 | 550165003464 |
oct | 124211310377 |
9 | 32166301360 |
10 | 11310305535 |
11 | 4884410a51 |
12 | 223796b853 |
13 | 10b32c30a9 |
14 | 7941a766b |
15 | 462e36990 |
hex | 2a22590ff |
11310305535 has 32 divisors (see below), whose sum is σ = 20143442880. Its totient is φ = 6021293184.
The previous prime is 11310305533. The next prime is 11310305537. The reversal of 11310305535 is 53550301311.
11310305535 is a `hidden beast` number, since 1 + 1 + 3 + 103 + 0 + 553 + 5 = 666.
11310305535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11310305533) and next prime (11310305537).
It is not a de Polignac number, because 11310305535 - 21 = 11310305533 is a prime.
It is a super-2 number, since 2×113103055352 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 11310305499 and 11310305508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310305533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12 + ... + 150401.
It is an arithmetic number, because the mean of its divisors is an integer number (629482590).
Almost surely, 211310305535 is an apocalyptic number.
11310305535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11310305535 is a deficient number, since it is larger than the sum of its proper divisors (8833137345).
11310305535 is a wasteful number, since it uses less digits than its factorization.
11310305535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150984 (or 150978 counting only the distinct ones).
The product of its (nonzero) digits is 3375, while the sum is 27.
Adding to 11310305535 its reverse (53550301311), we get a palindrome (64860606846).
The spelling of 11310305535 in words is "eleven billion, three hundred ten million, three hundred five thousand, five hundred thirty-five".
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