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113103111133 = 2313935377889
BaseRepresentation
bin110100101010101111…
…0001000001111011101
3101210221100110100121001
41221111132020033131
53323113344024013
6123543040110301
711112541403455
oct1512536101735
9353840410531
10113103111133
1143a6a837471
1219b06005391
13a88637403c
14568d38ad65
152e1e757ddd
hex1a557883dd

113103111133 has 8 divisors (see below), whose sum is σ = 118869710400. Its totient is φ = 107407267968.

The previous prime is 113103111109. The next prime is 113103111169. The reversal of 113103111133 is 331111301311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113103111133 - 25 = 113103111101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113103111133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113103111193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17685748 + ... + 17692141.

It is an arithmetic number, because the mean of its divisors is an integer number (14858713800).

Almost surely, 2113103111133 is an apocalyptic number.

It is an amenable number.

113103111133 is a deficient number, since it is larger than the sum of its proper divisors (5766599267).

113103111133 is a wasteful number, since it uses less digits than its factorization.

113103111133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35378051.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 113103111133 its reverse (331111301311), we get a palindrome (444214412444).

The spelling of 113103111133 in words is "one hundred thirteen billion, one hundred three million, one hundred eleven thousand, one hundred thirty-three".

Divisors: 1 23 139 3197 35377889 813691447 4917526571 113103111133