Base | Representation |
---|---|
bin | 10101000100010010… |
… | …11100101001010101 |
3 | 1002012020100210112122 |
4 | 22202021130221111 |
5 | 141130420221323 |
6 | 5110151225325 |
7 | 550165064333 |
oct | 124211345125 |
9 | 32166323478 |
10 | 11310320213 |
11 | 4884420a85 |
12 | 2237978245 |
13 | 10b32c998a |
14 | 7941acb53 |
15 | 462e3aec8 |
hex | 2a225ca55 |
11310320213 has 2 divisors, whose sum is σ = 11310320214. Its totient is φ = 11310320212.
The previous prime is 11310320191. The next prime is 11310320243. The reversal of 11310320213 is 31202301311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10343296804 + 967023409 = 101702^2 + 31097^2 .
It is a cyclic number.
It is not a de Polignac number, because 11310320213 - 216 = 11310254677 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11310320191 and 11310320200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310320243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655160106 + 5655160107.
It is an arithmetic number, because the mean of its divisors is an integer number (5655160107).
Almost surely, 211310320213 is an apocalyptic number.
It is an amenable number.
11310320213 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310320213 is an equidigital number, since it uses as much as digits as its factorization.
11310320213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11310320213 its reverse (31202301311), we get a palindrome (42512621524).
The spelling of 11310320213 in words is "eleven billion, three hundred ten million, three hundred twenty thousand, two hundred thirteen".
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