Base | Representation |
---|---|
bin | 1010010010010110001110… |
… | …1111001110000111010110 |
3 | 1111001020220210122110210002 |
4 | 2210211203233032013112 |
5 | 2440302014441311314 |
6 | 40015520145331302 |
7 | 2245100220365264 |
oct | 244454357160726 |
9 | 44036823573702 |
10 | 11310322213334 |
11 | 3670754036931 |
12 | 1328024036b32 |
13 | 6407359178b1 |
14 | 2b15cb553434 |
15 | 14931a171ade |
hex | a4963bce1d6 |
11310322213334 has 4 divisors (see below), whose sum is σ = 16965483320004. Its totient is φ = 5655161106666.
The previous prime is 11310322213313. The next prime is 11310322213339. The reversal of 11310322213334 is 43331222301311.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11310322213297 and 11310322213306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310322213339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2827580553332 + ... + 2827580553335.
It is an arithmetic number, because the mean of its divisors is an integer number (4241370830001).
Almost surely, 211310322213334 is an apocalyptic number.
11310322213334 is a deficient number, since it is larger than the sum of its proper divisors (5655161106670).
11310322213334 is an equidigital number, since it uses as much as digits as its factorization.
11310322213334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5655161106669.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 11310322213334 its reverse (43331222301311), we get a palindrome (54641544514645).
The spelling of 11310322213334 in words is "eleven trillion, three hundred ten billion, three hundred twenty-two million, two hundred thirteen thousand, three hundred thirty-four".
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