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11310340052203 = 15174902914253
BaseRepresentation
bin1010010010010110010011…
…0011010001010011101011
31111001020222001012210002221
42210211210303101103223
52440302034023132303
640015522023534511
72245100525123533
oct244454463212353
944036861183087
1011310340052203
1136707631104a5
121328029bba437
1364073952243a
142b15cda784c3
1514931b9e74bd
hexa4964cd14eb

11310340052203 has 4 divisors (see below), whose sum is σ = 11385242966608. Its totient is φ = 11235437137800.

The previous prime is 11310340052177. The next prime is 11310340052243. The reversal of 11310340052203 is 30225004301311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11310340052203 - 221 = 11310337955051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11310340052243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37451456976 + ... + 37451457277.

It is an arithmetic number, because the mean of its divisors is an integer number (2846310741652).

Almost surely, 211310340052203 is an apocalyptic number.

11310340052203 is a deficient number, since it is larger than the sum of its proper divisors (74902914405).

11310340052203 is an equidigital number, since it uses as much as digits as its factorization.

11310340052203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74902914404.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 11310340052203 its reverse (30225004301311), we get a palindrome (41535344353514).

The spelling of 11310340052203 in words is "eleven trillion, three hundred ten billion, three hundred forty million, fifty-two thousand, two hundred three".

Divisors: 1 151 74902914253 11310340052203