1131040011133 has 2 divisors, whose sum is σ = 1131040011134. Its totient is φ = 1131040011132.

The previous prime is 1131040011107. The next prime is 1131040011149. The reversal of 1131040011133 is 3311100401311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1014488099524 + 116551911609 = 1007218^2 + 341397^2 .

It is an emirp because it is prime and its reverse (3311100401311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131040011133 - 2²¹ = 1131037913981 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1131040011133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131040011163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565520005566 + 565520005567.

It is an arithmetic number, because the mean of its divisors is an integer number (565520005567).

Almost surely, 2^{1131040011133} is an apocalyptic number.

It is an amenable number.

1131040011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131040011133 is an equidigital number, since it uses as much as digits as its factorization.

1131040011133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1131040011133 its reverse (3311100401311), we get a palindrome (4442140412444).

The spelling of 1131040011133 in words is "one trillion, one hundred thirty-one billion, forty million, eleven thousand, one hundred thirty-three".