11310407006581 has 2 divisors, whose sum is σ = 11310407006582. Its totient is φ = 11310407006580.

The previous prime is 11310407006543. The next prime is 11310407006597. The reversal of 11310407006581 is 18560070401311.

It is a happy number.

11310407006581 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7469649760356 + 3840757246225 = 2733066^2 + 1959785^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310407006581 - 2³¹ = 11308259522933 is a prime.

It is a super-2 number, since 2×11310407006581² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11310407006581.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310407096581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655203503290 + 5655203503291.

It is an arithmetic number, because the mean of its divisors is an integer number (5655203503291).

Almost surely, 2^{11310407006581} is an apocalyptic number.

It is an amenable number.

11310407006581 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310407006581 is an equidigital number, since it uses as much as digits as its factorization.

11310407006581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 37.

Adding to 11310407006581 its reverse (18560070401311), we get a palindrome (29870477407892).

The spelling of 11310407006581 in words is "eleven trillion, three hundred ten billion, four hundred seven million, six thousand, five hundred eighty-one".