11311000423 has 2 divisors, whose sum is σ = 11311000424. Its totient is φ = 11311000422.

The previous prime is 11311000417. The next prime is 11311000427. The reversal of 11311000423 is 32400011311.

It is a strong prime.

It is an emirp because it is prime and its reverse (32400011311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11311000423 - 2⁹ = 11310999911 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311000397 and 11311000406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311000427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655500211 + 5655500212.

It is an arithmetic number, because the mean of its divisors is an integer number (5655500212).

Almost surely, 2^11311000423 is an apocalyptic number.

11311000423 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311000423 is an equidigital number, since it uses as much as digits as its factorization.

11311000423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11311000423 its reverse (32400011311), we get a palindrome (43711011734).

The spelling of 11311000423 in words is "eleven billion, three hundred eleven million, four hundred twenty-three", and thus it is an aban number.