11311003201433 has 4 divisors (see below), whose sum is σ = 12181080370788. Its totient is φ = 10440926032080.

The previous prime is 11311003201429. The next prime is 11311003201453. The reversal of 11311003201433 is 33410230011311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7179329048329 + 4131674153104 = 2679427^2 + 2032652^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311003201433 - 2² = 11311003201429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311003201399 and 11311003201408.

It is not an unprimeable number, because it can be changed into a prime (11311003201423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435038584658 + ... + 435038584683.

It is an arithmetic number, because the mean of its divisors is an integer number (3045270092697).

Almost surely, 2^{11311003201433} is an apocalyptic number.

11311003201433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11311003201433 is a deficient number, since it is larger than the sum of its proper divisors (870077169355).

11311003201433 is an equidigital number, since it uses as much as digits as its factorization.

11311003201433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870077169354.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11311003201433 its reverse (33410230011311), we get a palindrome (44721233212744).

The spelling of 11311003201433 in words is "eleven trillion, three hundred eleven billion, three million, two hundred one thousand, four hundred thirty-three".