Base | Representation |
---|---|
bin | 1010010010011000110010… |
… | …1111110001010101110010 |
3 | 1111001022200202021000021010 |
4 | 2210212030233301111302 |
5 | 2440304422104122344 |
6 | 40020112324011350 |
7 | 2245123243361613 |
oct | 244461457612562 |
9 | 44038622230233 |
10 | 11311010223474 |
11 | 3670a77437055 |
12 | 1328196530b56 |
13 | 6408153197a0 |
14 | 2b1654a89c0a |
15 | 14935a7768b9 |
hex | a498cbf1572 |
11311010223474 has 64 divisors (see below), whose sum is σ = 24904808570880. Its totient is φ = 3403409570880.
The previous prime is 11311010223473. The next prime is 11311010223493. The reversal of 11311010223474 is 47432201011311.
11311010223474 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×113110102234743 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11311010223473) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5555172 + ... + 7313135.
It is an arithmetic number, because the mean of its divisors is an integer number (389137633920).
Almost surely, 211311010223474 is an apocalyptic number.
11311010223474 is an abundant number, since it is smaller than the sum of its proper divisors (13593798347406).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11311010223474 is a wasteful number, since it uses less digits than its factorization.
11311010223474 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12868575.
The product of its (nonzero) digits is 4032, while the sum is 30.
Adding to 11311010223474 its reverse (47432201011311), we get a palindrome (58743211234785).
The spelling of 11311010223474 in words is "eleven trillion, three hundred eleven billion, ten million, two hundred twenty-three thousand, four hundred seventy-four".
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